Comparing the values of two generic Numbers

After having asked a similar question and studying the answers here, I came up with the following. I think it is more efficient and more robust than the solution given by gustafc:

public int compare(Number x, Number y) {
    if (isSpecial(x) || isSpecial(y))
        return Double.compare(x.doubleValue(), y.doubleValue());
    else
        return toBigDecimal(x).compareTo(toBigDecimal(y));
}

private static boolean isSpecial(Number x) {
    var specialDouble = x instanceof Double d
            && (Double.isNaN(d) || Double.isInfinite(d));
    var specialFloat = x instanceof Float f
            && (Float.isNaN(f) || Float.isInfinite(f));
    return specialDouble || specialFloat;
}

private static BigDecimal toBigDecimal(Number number) {
    if (number instanceof BigDecimal d)
        return d;
    if (number instanceof BigInteger i)
        return new BigDecimal(i);
    if (number instanceof Byte || number instanceof Short
            || number instanceof Integer || number instanceof Long)
        return new BigDecimal(number.longValue());
    if (number instanceof Float || number instanceof Double)
        return new BigDecimal(number.doubleValue());
    
    try {
        return new BigDecimal(number.toString());
    } catch(NumberFormatException e) {
        throw new RuntimeException("The given number (\"" + number + "\" of class " + number.getClass().getName() + ") does not have a parsable string representation", e);
    }
}