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I'm trying to expose this function to Python using SWIG: std::vector<int> get_match_stats(); And I want SWIG to generate wrapping code for Python so I can see it as a list of integers. Adding this to the .i file: %include "typemaps.i" %include "std_vector.i" namespace std { %template(IntVector) vector<int>; } I'm running SWIG Version 1.3.36 and calling swig with -Wall and I get no warnings. I'm able to get access to a list but I get a bunch of warnings when compiling with -Wall (with g++ (GCC) 4.2.4 ) the generated C++ code that say: warning: dereferencing type-punned pointer will break strict-aliasing rules Am I exposing the function correctly? If so, what does the warning mean? These are the lines before the offending line in the same function: SWIGINTERN PyObject *_wrap_IntVector_erase__SWIG_0(PyObject *SWIGUNUSEDPARM(self), PyObject *args) { PyObject *resultobj = 0; std::vector *arg1 = (std::vector *) 0 ; std::vector::iterator arg2 ; std::vector::iterator result; void *argp1 = 0 ; int res1 = 0 ; swig::PySwigIterator *iter2 = 0 ; int res2 ; PyObject * obj0 = 0 ; PyObject * obj1 = 0 ; if (!PyArg_ParseTuple(args,(char *)"OO:IntVector_erase",&obj0,&obj1)) SWIG_fail; res1 = SWIG_ConvertPtr(obj0, &argp1,SWIGTYPE_p_std__vectorT_int_std__allocatorT_int_t_t, 0 | 0 ); if (!SWIG_IsOK(res1)) { SWIG_exception_fail(SWIG_ArgError(res1), "in method '" "IntVector_erase" "', argument " "1"" of type '" "std::vector *""'"); } arg1 = reinterpret_cast * >(argp1); And this is the offending line: res2 = SWIG_ConvertPtr(obj1, SWIG_as_voidptrptr(&iter2), swig::PySwigIterator::descriptor(), 0); More code follows that. The warning generated when compiling with g++ 4.2.4 is: swig_iss_wrap.cxx: In function ‘PyObjec

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