I have URLs like http://example.com/depict?smiles=CO&width=200&height=200 (and with several other optional arguments)

My urls.py contains:

urlpatterns = patterns('',
    (r'^$', 'cansmi.index'),
    (r'^cansmi$', 'cansmi.cansmi'),
    url(r'^depict$', cyclops.django.depict, name="cyclops-depict"),

I can go to that URL and get the 200x200 PNG that was constructed, so I know that part works.

In my template from the "cansmi.cansmi" response I want to construct a URL for the named template "cyclops-depict" given some query parameters. I thought I could do

{% url cyclops-depict smiles=input_smiles width=200 height=200 %}

where "input_smiles" is an input to the template via a form submission. In this case it's the string "CO" and I thought it would create a URL like the one at top.

This template fails with a TemplateSyntaxError:

Caught an exception while rendering: Reverse for 'cyclops-depict' with arguments '()' and keyword arguments '{'smiles': u'CO', 'height': 200, 'width': 200}' not found.

This is a rather common error message both here on StackOverflow and elsewhere. In every case I found, people were using them with parameters in the URL path regexp, which is not the case I have where the parameters go into the query.

That means I'm doing it wrong. How do I do it right? That is, I want to construct the full URL, including path and query parameters, using something in the template.

For reference,

% python manage.py shell
Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) 
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from django.core.urlresolvers import reverse
>>> reverse("c
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