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Alex Rivera
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I want to match the last occurrence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2") print "last match: ", list[len(list)-1] However, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurrence of " AAAA ", or should I use this workaround?
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