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How to completely remove a dialog on close

Asked 2010-05-19T10:42:56.357
140

When an ajax operation fails, I create a new div with the errors and then show it as a dialog. When the dialog is closed I would like to completely destroy and remove the div again. How can I do this? My code looks something like this at the moment:

$('<div>We failed</div>')
    .dialog(
    {
        title: 'Error',
        close: function(event, ui)
        {
            $(this).destroy().remove();
        }
    });

When I run this the dialog box shows up correctly, but when I close it the dialog is still visible in the html (using FireBug). What am I missing here? Something I have forgotten?

Update: Just noticed my code gives me an error in the firebug console.

$(this).destroy is not a function

Anyone able to help me out?

Update: If I do just $(this).remove() instead, the item is removed from the html. But is it completely removed from the DOM? Or do I somehow need to call that destroy function first as well?

jquery-ui jquery-ui-dialog
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2 Answers

11

Why do you want to remove it?

If it is to prevent multiple instances being created, then just use the following approach...

$('#myDialog') 
    .dialog( 
    { 
        title: 'Error', 
        close: function(event, ui) 
        { 
            $(this).dialog('close');
        } 
    });

And when the error occurs, you would do...

$('#myDialog').html("Ooops.");
$('#myDialog').dialog('open');
answered 2010-05-19T10:51:07.587
2

An ugly solution that works like a charm for me:

$("#mydialog").dialog(
    open: function(){
        $('div.ui-widget-overlay').hide();
        $("div.ui-dialog").not(':first').remove();
}
});
answered 2012-11-15T13:33:38.110

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