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pure-specifier on function-definition

Asked 2010-06-01T15:56:10.667
40

While compiling on GCC I get the error: pure-specifier on function-definition, but not when I compile the same code using VS2005.

class Dummy {   
  //error: pure-specifier on function-definition, VS2005 compiles 
  virtual void Process() = 0 {};
};

But when the definition of this pure virtual function is not inline, it works:

class Dummy
{
  virtual void Process() = 0;
};
void Dummy::Process()
{} //compiles on both GCC and VS2005

What does the error means? Why cannot I do it inline? Is it legal to evade the compile issue as shown in the second code sample?

c++ abstract-class pure-virtual
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1 Answer

41

Ok, I've just learned something. A pure virtual function must be declared as follows:


class Abstract 
{
public:
   virtual void pure_virtual() = 0;
};

It may have a body, although it is illegal to include it at the point of declaration. This means that to have a body the pure virtual function must be defined outside the class. Note that even if it has a body, the function must still be overridden by any concrete classes derived from Abstract. They would just have an option to call Abstract::pure_virtual() explicitly if they need to.

The details are here.

answered 2010-06-01T15:58:57.927

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