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How to start a process in the same folder as its executable

Asked 2010-06-04T09:41:35.430
10

I'm trying to start an application programatically, but it always runs it in the folder of my application... For example:

If my app is located in C:\MyApp\myapp.exe and the other app is in C:\OtherApp\otherapp.exe, how can I start the other app in the folder in which it resides, rather than in the folder where my app resides?

Here is how I start the other app:

private void StartApp(OtherApp application)
{
    Process process = new Process();
    process.StartInfo.FileName = application.FileName;
    process.StartInfo.Arguments = application.AppName;
    process.Start();
}
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6

Just set the WorkDirectory property.

process.StartInfo.WorkingDirectory = Path.GetDirectoryName(application.Filename);
answered 2010-06-04T09:46:26.383

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