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I am using a jQuery AJAX request to a page called like.php that connects to my database and inserts a row. This is the like.php code: <?php // Some config stuff define(DB_HOST, 'localhost'); define(DB_USER, 'root'); define(DB_PASS, ''); define(DB_NAME, 'quicklike'); $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('ERROR: ' . mysql_error()); $sel = mysql_select_db(DB_NAME, $link) or die('ERROR: ' . mysql_error()); $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); $timeStamp = time(); if(empty($likeMsg)) die('ERROR: Message is empty'); $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; $result = mysql_query($sql, $link) or die('ERROR: ' . mysql_error()); echo mysql_insert_id(); mysql_close($link); ?> The problematic line is $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); . It seems to just return an empty string, and in my database under the like_message column all I see is blank entries. If I remove mysql_real_escape_string() though, it works fine. Here's my jQuery code if it helps. $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMessage = $('#changer p').html(); if(likeMessage) { $.ajax({ cache: false, url: 'like.php', type: 'POST', data: { likeMsg: likeMessage }, success: function(data) { $('#like').unbind(); writeLikeButton(data); } }); } else { $('#button_container').html(''); } } }); All this jQuery code works fine, I've tested it myself independently. Any help is greatly appreciated, thanks.

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