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How to get the path of the current class, from an inherited method? I have the following: <?php // file: /parentDir/class.php class Parent { protected function getDir() { return dirname(__FILE__); } } ?> and <?php // file: /childDir/class.php class Child extends Parent { public function __construct() { echo $this->getDir(); } } $tmp = new Child(); // output: '/parentDir' ?> The __FILE__ constant always points to the source-file of the file it is in, regardless of inheritance. I would like to get the name of the path for the derived class. Is there any elegant way of doing this? I could do something along the lines of $this->getDir(__FILE__); but that would mean that I have to repeat myself quite often. I'm looking for a method that puts all the logic in the parent class, if possible. Update: Accepted solution (by Palantir ): <?php // file: /parentDir/class.php class Parent { protected function getDir() { $reflector = new ReflectionClass(get_class($this)); return dirname($reflector->getFileName()); } } ?>

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