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Alex Rivera
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Running the following (example) code import java.io.*; public class test { public static void main(String[] args) throws Exception { byte[] buf = {-27}; InputStream is = new ByteArrayInputStream(buf); BufferedReader r = new BufferedReader( new InputStreamReader(is, "ISO-8859-1")); String s = r.readLine(); System.out.println("test.java:9 [byte] (char)" + (char)s.getBytes()[0] + " (int)" + (int)s.getBytes()[0]); System.out.println("test.java:10 [char] (char)" + (char)s.charAt(0) + " (int)" + (int)s.charAt(0)); System.out.println("test.java:11 string below"); System.out.println(s); System.out.println("test.java:13 string above"); } } gives me this output test.java:9 [byte] (char)? (int)63 test.java:10 [char] (char)? (int)229 test.java:11 string below ? test.java:13 string above How do I retain the correct byte value (-27) in the line-9 printout? And consequently receive the expected output of the System.out.println(s) command (å).
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