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Substitute the n-th occurrence of a word in vim

Asked 2010-06-19T00:39:59.780
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I saw other questions dealing with the finding the n-th occurrence of a word/pattern, but I couldn't find how you would actually substitute the n-th occurrence of a pattern in vim. There's the obvious way of hard coding all the occurrences like 

:s/.*\(word\).*\(word\).*\(word\).*/.*\1.*\2.*newWord.*/g

Is there a better way of doing this?

regex vim sed substitution
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Well, if you do /gc then you can count the number of times it asks you for confirmation, and go ahead with the replacement when you get to the nth :D

answered 2010-06-19T00:43:51.067

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