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Alex Rivera
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I have a table structure that looks like: <table> <tr id="row1"> <td> <div>row 1 content1</div> </td> <td> <div>row 1 content2</div> </td> <td> <div>row 1 content3</div> </td> </tr> <tr id="row2"> <td> <div>row 2 content1</div> </td> <td> <div>row 2 content2</div> </td> <td> <div>row 2 content3</div> </td> </tr> <tr id="row3"> <td> <div>row 3 content1</div> </td> <td> <div>row 3 content2</div> </td> <td> <div>row 3 content3</div> </td> </tr> </table> Using jQuery I am trying to select the DIV in the second cell of the third row. I tried the following (amongst other things): var d = $('#row3').children(':eq(1)').children(':eq(0)'); What I get back is an array with a single element (the DIV I'm after) and I have to then access using d[0]. Why is jQuery returning a single element array, I thought using the selector above would return the DIV element directly? @Shog9 - Duh...Ok a light just switched on in my brain, I get it now. Cheers.
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