10
This SQL statement works if I run it from my Oracle client (SQL Developer):
insert into Person (Name) select 'Bob' from dual
It also works if I issue it via Spring JDBC, without using a KeyHolder:
final PreparedStatementCreator psc = new PreparedStatementCreator() {
@Override
public PreparedStatement createPreparedStatement(Connection con)
throws SQLException
{
return con.prepareStatement(
"insert into Person (Name) select 'Bob' from dual");
}
};
jdbcOperations.update(psc);
However I need to use a KeyHolder in order to get the ID of the newly inserted row. If I alter the above code to use a KeyHolder as follows:
final KeyHolder keyHolder = new GeneratedKeyHolder();
final PreparedStatementCreator psc = new PreparedStatementCreator() {
@Override
public PreparedStatement createPreparedStatement(Connection con)
throws SQLException
{
return con.prepareStatement(
"insert into Person (Name) select 'Bob' from dual",
new String[] {"PersonID"});
}
};
jdbcOperations.update(psc, keyHolder);
... then I get this error:
Exception in thread "main" org.springframework.jdbc.BadSqlGrammarException: PreparedStatementCallback; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: ORA-00933: SQL command not properly ended
at org.springframework.jdbc.support.SQLExceptionSubclassTranslator.doTranslate(SQLExceptionSubclassTranslator.java:94)
at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:72)
at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java: