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How can I tell the inheriting class to not call its base class' parameter-less constructor?

Asked 2010-07-16T14:37:47.823
12

I was surprised to find out that the parameter-less constructor of my base class is called any time I call any constructor in a derived class. I thought that is what : base() was for, to explicitly call the base constructor if and when I want to.

How can I prevent the base constructor from being called when I instantiate a derived class?

using System;

namespace TestConstru22323
{
    class Program
    {
        static void Main(string[] args)
        {
            Customer customer = new Customer("Jim", "Smith");
            Customer c = new Customer();
            Console.WriteLine(customer.Display());

            Console.ReadLine();
        }
    }

    public class Person
    {
        public Person()
        {
            Console.WriteLine("I don't always want this constructor to be called. I want to call it explicitly.");
        }
    }

    public class Customer : Person
    {
        private string _firstName;
        private string _lastName;

        //public Customer(string firstName, string lastName): base()  //this explicitly calls base empty constructor
        public Customer(string firstName, string lastName) //but this calls it anyway, why?
        {
            _firstName = firstName;
            _lastName = lastName;
        }

        public string Display()
        {
            return String.Format("{0}, {1}", _lastName, _firstName);
        }
    }
}
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1 Answer

8

In .NET, every object constructor in an object hierarchy will be called regardless if you call :base() or not.

:base() is implicitly called if you don't explicitly call it.

:base() can be used if you want to call a different contructor on a parent object rather than the default constructor.

If you have code in the parent constructor that should not be called everytime, it may be better to move that code to it's own method that will need to be called explicitly after the object is constructed. Or, create a parameterized constructor on the parent object and use the parameter to determine if the code should be executed or not.

For example:

:base(true) - This executes your code.
:base(false) - This does not execute your code.
answered 2010-07-16T14:53:20.247

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