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SQL group by day, show orders for each day

Asked 2008-11-30T22:06:28.410
15

I have an SQL 2005 table, let's call it Orders, in the format:

OrderID, OrderDate,  OrderAmount
1,       25/11/2008, 10
2,       25/11/2008, 2
3,       30/1002008, 5

Then I need to produce a report table showing the ordered amount on each day in the last 7 days:

Day,        OrderCount, OrderAmount
25/11/2008, 2,          12
26/11/2008, 0,          0 
27/11/2008, 0,          0 
28/11/2008, 0,          0
29/11/2008, 0,          0
30/11/2008, 1,          5

The SQL query that would normally produce this:

select count(*), sum(OrderAmount)
    from Orders
    where OrderDate>getdate()-7
    group by datepart(day,OrderDate)

Has a problem in that it will skip the days where there are no orders:

Day,        OrderCount, OrderAmount
25/11/2008, 2,          12
30/11/2008, 1,          5

Normally I would fix this using a tally table and outer join against rows there, but I'm really looking for a simpler or more efficient solution for this. It seems like such a common requirement for a report query that some elegant solution should be available for this already.

So: 1. Can this result be obtain from a simple query without using tally tables?

and 2. If no, can we create this tally table (reliably) on the fly (I can create a tally table using CTE but recursion stack limits me to 100 rows)?

sql sql-server-2005 aggregate
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2 Answers

1

Depending on how SQL Server handles temporary tables, you can more or less easily arrange to create a temporary table and populate it with the 7 (or was that 8?) dates you are interested in. You can then use that as your tally table. There isn't a cleaner way that I know of; you can only select data that exists in a table or that can be derived from data that exists in a table or set of tables. If there are dates not represented in the Orders table, you can't select those dates from the Orders table.

answered 2008-11-30T22:24:19.590
1

If you want to see value zero than put the following query:

select count(*), sum(OrderAmount)
from Orders
where OrderDate>getdate()-7
  and sum(OrderAmount) > 0 or sum(OrderAmount) = 0
group by datepart(day,OrderDate)
answered 2010-08-21T20:12:53.323

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