Three-way conditional in c++ to determine sign equivalance of two numbers

I need the most efficient way (in cpu cycles) to determine if two numbers have the same/different sign. But the catch is if either number is zero I need to be able to distinguish it from numbers with same/different signs (ie. zero is treated as a "third" sign). The following code is similar to what I need, but the return values can be anything as long as there are only three distinct return values.

int foo(int x, int y) {
    if (x * y > 0) return 1;
    if (x * y < 0) return -1;
    return 0;
}

For my specific problem, the values are in the range [-6, 6] and X is guaranteed to not be 0. I found a solution to find if two numbers have the same sign, and altered it to get the following solution.

return y? (((x^y) >= 0)? 1 : -1) : 0;

There should be some bitops/comparisons that give faster results than using multiplication, branching, comparisons.