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Hi I had performed a transformation which drops a tag if it is null. I wanted to check whether my transformation is working fine, so instead of checking it manually, I wrote one more XSLT code which just checks the presence of that particular tag in the OUTPUT XML, if it is null, then the second XSLT should output a text "FOUND". (I don't actually need some XML kind of output but I am just using XSLT for searching.) When I tried with this XSL code :: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/SiebelMessage//SuppressCalendar[.!='']"> FOUND </xsl:template> </xsl:stylesheet> It outputs all the TEXT DATA that is present in the XML file, to avoid that, I had to write this code:: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/SiebelMessage//SuppressCalendar[.!='']"> FOUND </xsl:template> <xsl:template match="text()"/> </xsl:stylesheet> why did the former code outputs TEXT, why should I insist XSL to ignore all other text? is that the behavior of all XML parsers or only of my own (I am using msxml parser).

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