C++ Passing Pointer to Function (Howto) + C++ Pointer Manipulation

I am a little confused as to how passing pointers works.

Let's say I have the following function and pointer, and...

EDIT:

...I want to use a pointer to some object as an argument in the function.

i.e.:

void Fun(int Pointer){
    int Fun_Ptr = ---Passed Pointer---; 
    //So that Fun_Ptr points to whatever ---Passed Pointer points to

Between the *Pointer and &Pointer notations, I am very confused. I know that *Pointer means give whatever it points to.

Do I put void (int *pointer) in the declaration. What about when I use the function?

Your assistance is appreciated.

EDIT 2:

Okay, I now understand that using *variable in a declaration means that a pointer will be passed. However, what about when i use the function?

i.e.

int main(){
    int foo;
    int *bar;
    bar = foo;
    Fun(bar);
}

EDIT 3: Okay, so correct me if I am wrong:

According to the conventions of the above code:

bar = &foo means: Make bar point to foo in memory

*bar = foo means Change the value that bar points to to equal whatever foo equals

If I have a second pointer (int *oof), then:

bar = oof means: bar points to the oof pointer

bar = *oof means: bar points to the value that oof points to, but not to the oof pointer itself

*bar = *oof means: change the value that bar points to to the value that oof points to

&bar = &oof means: change the memory address that bar points to be the same as the memory address that oof points to

Do I have this right?

EDIT 4: Thanks so much for all your help (I wish I could accept more than 1 answer, but I have to go with the first one. I am not sure how a community wiki works exactly, but I will leave it this way for editing (feel free to turn it into a ref guide if you like).