Have created a c++ implementation of the Hough transform for detecting lines in images. Found lines are represented using rho, theta, as described on wikipedia:

"The parameter r represents the distance between the line and the origin, while θ is the angle of the vector from the origin to this closest point "

How can i find the intersection point in x, y space for two lines described using r, θ?

For reference here are my current functions for converting in and out of hough space:

//get 'r' (length of a line from pole (corner, 0,0, distance from center) perpendicular to a line intersecting point x,y at a given angle) given the point and the angle (in radians)
inline float point2Hough(int x, int y, float theta) {
    return((((float)x)*cosf(theta))+((float)y)*sinf(theta));
}

//get point y for a line at angle theta with a distance from the pole of r intersecting x? bad explanation! >_<
inline float hough2Point(int x, int r, float theta) {
    float y;
    if(theta!=0) {
            y=(-cosf(theta)/sinf(theta))*x+((float)r/sinf(theta));
    } else {
            y=(float)r; //wth theta may == 0?!
    }
    return(y);
}

sorry in advance if this is something obvious..

c math image-processing geometry
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