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Booleans, conditional operators and autoboxing

Asked 2010-10-07T13:28:51.967
137

Why does this throw NullPointerException

public static void main(String[] args) throws Exception {
    Boolean b = true ? returnsNull() : false; // NPE on this line.
    System.out.println(b);
}

public static Boolean returnsNull() {
    return null;
}

while this doesn't

public static void main(String[] args) throws Exception {
    Boolean b = true ? null : false;
    System.out.println(b); // null
}

?

The solution is by the way to replace false by Boolean.FALSE to avoid null being unboxed to boolean --which isn't possible. But that isn't the question. The question is why? Are there any references in JLS which confirms this behaviour, especially of the 2nd case?

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1 Answer

17

From Java Language Specification, section 15.25:

  • If one of the second and third operands is of type boolean and the type of the other is of type Boolean, then the type of the conditional expression is boolean.

So, the first example tries to call Boolean.booleanValue() in order to convert Boolean to boolean as per the first rule.

In the second case the first operand is of the null type, when the second is not of the reference type, so autoboxing conversion is applied:

  • Otherwise, the second and third operands are of types S1 and S2 respectively. Let T1 be the type that results from applying boxing conversion to S1, and let T2 be the type that results from applying boxing conversion to S2. The type of the conditional expression is the result of applying capture conversion (§5.1.10) to lub(T1, T2) (§15.12.2.7).
answered 2010-10-07T13:41:27.430

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