520
Since Java 1.5, String.format() can be used to left/right pad a given string.
public static String padRight(String s, int n) {
return String.format("%-" + n + "s", s);
}
public static String padLeft(String s, int n) {
return String.format("%" + n + "s", s);
}
...
public static void main(String args[]) throws Exception {
System.out.println(padRight("Howto", 20) + "*");
System.out.println(padLeft("Howto", 20) + "*");
}
And the output is:
Howto *
Howto*
i know this thread is kind of old and the original question was for an easy solution but if it's supposed to be really fast, you should use a char array.
public static String pad(String str, int size, char padChar)
{
if (str.length() < size)
{
char[] temp = new char[size];
int i = 0;
while (i < str.length())
{
temp[i] = str.charAt(i);
i++;
}
while (i < size)
{
temp[i] = padChar;
i++;
}
str = new String(temp);
}
return str;
}
the formatter solution is not optimal. just building the format string creates 2 new strings.
apache's solution can be improved by initializing the sb with the target size so replacing below
StringBuffer padded = new StringBuffer(str);
with
StringBuffer padded = new StringBuffer(pad);
padded.append(value);
would prevent the sb's internal buffer from growing.
Here is another way to pad to the right:
// put the number of spaces, or any character you like, in your paddedString
String paddedString = "--------------------";
String myStringToBePadded = "I like donuts";
myStringToBePadded = myStringToBePadded + paddedString.substring(myStringToBePadded.length());
//result:
myStringToBePadded = "I like donuts-------";