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C : is there "lazy evaluation" when using && operator, as in C++?

Asked 2010-10-18T11:59:07.310
19

I would like to know if this looks correct :

while((next !=NULL) && (strcmp(next->name, some_string) < 0) {
    //some process
}

I mean, if next is NULL, then the second part of the expression won't be ever tested by the compiler? I have heard that in C++ it's the case (but I'm not even sure of it).

Can someone confirm me that I won't get strange errors on some compilers with that?

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10

It's definitely the case in both C and C++.

answered 2010-10-18T12:00:50.850

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