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How can I format my grep output to show line numbers at the end of the line, and also the hit count?

Asked 2010-10-19T12:06:02.317
445

I'm using grep to match string in a file. Here is an example file:

example one,
example two null,
example three,
example four null,

grep -i null myfile.txt returns 

example two null,
example four null,

How can I return matched lines together with their line numbers like this:

  example two null, - Line number : 2
  example four null, - Line number : 4
  Total null count : 2

I know -c returns total matched lines, but I don't how to format it properly to add total null count in front, and I don't know how to add the line numbers.

What can I do?

linux bash unix grep
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1 Answer

4

grep find the lines and output the line numbers, but does not let you "program" other things. If you want to include arbitrary text and do other "programming", you can use awk,

$ awk '/null/{c++;print $0," - Line number: "NR}END{print "Total null count: "c}' file
example two null,  - Line number: 2
example four null,  - Line number: 4
Total null count: 2

Or only using the shell(bash/ksh)

c=0
while read -r line
do
  case "$line" in
   *null* )  (
    ((c++))
    echo "$line - Line number $c"
    ;;
  esac
done < "file"
echo "total count: $c"
answered 2010-10-19T12:13:44.090

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