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How to retrieve element value of XML using Java?

Asked 2010-11-02T10:47:38.223
56

I am new to XML. I want to read the following XML on the basis of request name. Please help me on how to read the below XML in Java -

<?xml version="1.0"?>
    <config>
        <Request name="ValidateEmailRequest">
            <requestqueue>emailrequest</requestqueue>
            <responsequeue>emailresponse</responsequeue>
        </Request>
        <Request name="CleanEmail">
            <requestqueue>Cleanrequest</requestqueue>
            <responsequeue>Cleanresponse</responsequeue>
        </Request>
    </config>
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You can make a class which extends org.xml.sax.helpers.DefaultHandler and call

start_<tag_name>(Attributes attrs);

and

end_<tag_name>();

For it is:

start_request_queue(attrs);

etc.

And then extends that class and implement xml configuration file parsers you want. Example:

  ...
  public void startElement(String uri, String name, String qname,
                           org.xml.sax.Attributes attrs) 
                  throws org.xml.sax.SAXException {
    Class[] args = new Class[2];
    args[0] = uri.getClass();
    args[1] = org.xml.sax.Attributes.class;
    try {
      String mname = name.replace("-", "");
      java.lang.reflect.Method m = 
            getClass().getDeclaredMethod("start" + mname, args);
      m.invoke(this, new Object[] { uri, (org.xml.sax.Attributes)attrs }); 
    }
catch (IllegalAccessException e) { throw new RuntimeException(e); }
catch (NoSuchMethodException e) { throw new RuntimeException(e); }
catch (java.lang.reflect.InvocationTargetException e) { org.xml.sax.SAXException se = new org.xml.sax.SAXException(e.getTargetException()); se.setStackTrace(e.getTargetException().getStackTrace()); }

and in a particular configuration parser:

   public void start_Request(String uri, org.xml.sax.Attributes attrs) {
     // make sure to read attributes correctly
     System.err.println("Request, name="+ attrs.getValue(0);
   }

answered 2010-11-02T12:01:52.977

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