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Alex Rivera
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Is there any syntax for using a decorator on a lambda function in Python? Example: def simpledecorator(f): def new_f(): print "Using a decorator: " f() return new_f @simpledecorator def hello(): print "Hello world!" Results in this output: >>> hello() Using a simple decorator: Hello world! Yet when I try the same with a lambda: @anotherdecorator f = lambda x: x * 2 I get this: File "<stdin", line 2 f = lambda x: x * 2 ^ SyntaxError: invalid syntax I feel like this might be a good way to make lambdas more versatile by allowing statements to be "injected" into them. But if there exists such a feature, I don't know what the syntax is.
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