KnowledgeHub
Questions
Tags
Users
Search
Alex Rivera
|
Logout
Edit Question
Title
Body
In ANSI C++, how can I assign the cout stream to a variable name? What I want to do is, if the user has specified an output file name, I send output there, otherwise, send it to the screen. So something like: ofstream outFile; if (outFileRequested) outFile.open("foo.txt", ios::out); else outFile = cout; // Will not compile because outFile does not have an // assignment operator outFile << "whatever" << endl; I tried doing this as a Macro function as well: #define OUTPUT outFileRequested?outFile:cout OUTPUT << "whatever" << endl; But that gave me a compiler error as well. I supposed I could either use an IF-THEN block for every output, but I'd like to avoid that if I could. Any ideas?
Tags (comma-separated)
Save Edits
Cancel