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Alex Rivera
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Can anyone please explain why this compiles and why does t end up with type int& ? #include <utility> void f(int& r) { ++r; } template <typename Fun, typename T> void g(Fun fun, T&& t) { fun(std::forward<T>(t)); } int main() { int i = 0; g(f, i); } I see this on GCC 4.5.0 20100604 and GDB 7.2-60.2
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