As reference, I'm using the following code:
#include <stdio.h>
#include <string.h>
int main (void) {
char buf[100]; // ------> How do I find the address in gdb?
printf ("Buffer is at memory location: %08x\n", &buf);
strcpy (buf, "some random text");
printf ("Text is [%s]\n", buf);
return 0;
}
How can I get gdb to show me the address of the buf variable?
If you enter the following into gdb, you'll get the address:
start
p &buf
as in the following transcript:
pax$ gdb ./qq.exe
GNU gdb 6.8.0.20080328-cvs (cygwin-special)
Copyright (C) 2008 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law. Type "show copying"
and "show warranty" for details.
This GDB was configured as "i686-pc-cygwin"...
(gdb) start
Breakpoint 1 at 0x401144: file qq.c, line 2.
Starting program: /home/pax/qq.exe
[New thread 2912.0xf9c]
[New thread 2912.0x518]
main () at qq.c:2
2 int main (int argc, char **argv) {
(gdb) p &buf
$1 = (char (*)[100]) 0x22ccd0
(gdb)