KnowledgeHub
Questions
Tags
Users
Search
Alex Rivera
|
Logout
Edit Question
Title
Body
I've read a few tutorials and examples, but I cannot wrap my head around how the MUL instruction works. I've used ADD and SUB without problems. So apparently this instruction multiplies its operand by the value in a register. What register (eax, ebp, esp, etc.) is multiplied by the first operand? And what register is the result stored in, so I can move it to the stack? Sorry, I'm just learning x86 assembly. When I try to compile this line... mul 9 I get, Error: suffix or operands invalid for 'mul' . Can anyone help me out? global main main: push ebp movl ebp, esp sub esp, byte +8 mov eax, 7 mul 9 mov [esp], eax call _putchar xor eax, eax leave ret
Tags (comma-separated)
Save Edits
Cancel