What is the difference between Θ(n) and O(n)?

Short explanation:

If an algorithm is of Θ(g(n)), it means that the running time of the algorithm as n (input size) gets larger is proportional to g(n).

If an algorithm is of O(g(n)), it means that the running time of the algorithm as n gets larger is at most proportional to g(n).

Normally, even when people talk about O(g(n)) they actually mean Θ(g(n)) but technically, there is a difference.

More technically:

O(n) represents upper bound. Θ(n) means tight bound. Ω(n) represents lower bound.

f(x) = Θ(g(x)) iff f(x) = O(g(x)) and f(x) = Ω(g(x))

Basically when we say an algorithm is of O(n), it's also O(n²), O(n^1000000), O(2ⁿ), ... but a Θ(n) algorithm is not Θ(n²).

In fact, since f(n) = Θ(g(n)) means for sufficiently large values of n, f(n) can be bound within c₁g(n) and c₂g(n) for some values of c₁ and c₂, i.e. the growth rate of f is asymptotically equal to g: g can be a lower bound and and an upper bound of f. This directly implies f can be a lower bound and an upper bound of g as well. Consequently,

f(x) = Θ(g(x)) iff g(x) = Θ(f(x))

Similarly, to show f(n) = Θ(g(n)), it's enough to show g is an upper bound of f (i.e. f(n) = O(g(n))) and f is a lower bound of g (i.e. f(n) = Ω(g(n)) which is the exact same thing as g(n) = O(f(n))). Concisely,

f(x) = Θ(g(x)) iff f(x) = O(g(x)) and g(x) = O(f(x))

There are also little-oh and little-omega (ω) notations representing loose upper and loose lower bounds of a function.

To summarize:

f(x) = O(g(x)) (big-oh) means that the growth rate of f(x) is asymptotica

Rather than provide a theoretical definition, which are beautifully summarized here already, I'll give a simple example:

Assume the run time of f(i) is O(1). Below is a code fragment whose asymptotic runtime is Θ(n). It always calls the function f(...) n times. Both the lower and the upper bound is n.

for(int i=0; i<n; i++){
    f(i);
}

The second code fragment below has the asymptotic runtime of O(n). It calls the function f(...) at most n times. The upper bound is n, but the lower bound could be Ω(1) or Ω(log(n)), depending on what happens inside f2(i).

for(int i=0; i<n; i++){
    if( f2(i) ) break;
    f(i);
}