11
A simple way is too loop over the rows
nRows = size(start,1);
finish = cell(nRows,1);
for r = 1:nRows
finish{r} = [start{r,:}];
end
EDIT
A more involved and slightly harder to read solution that does the same (the general solution is left as an exercise for the reader)
finish = accumarray([1 1 1 2 2 2]',[ 1 3 5 2 4 6]',[],@(x){[start{x}]})