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Alex Rivera
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I have a model: class Setting(models.Model): class Meta: abstract = True name = models.CharField(max_length=120, primary_key=True) description = models.CharField(max_length=300, blank=True) class IntegerSetting(Setting): value = models.IntegerField() I would like to create a form that looks something like: <form method="POST" action=""> {% for model in models %} <label>{{model.name}}</label> <input value='{{model.value}}' /> <p>{{model.description}}</p> {% endfor %} </form> I'm not quite sure how to go about doing this. Perhaps I need to use a formset? from django.forms.models import modelformset_factory from apps.about.models import Setting, IntegerSetting def site_settings(request): formset = modelformset_factory(IntegerSetting)() return render_to_response("about/admin/site-settings.html", {'formset': formset}, RequestContext(request, {})) Then in the template, I'd want to render the form differently than default. I'm not quite sure how to go about accessing the model properties, however. Is this the right approach, or is there another way I should be going about doing this? Update : This is what I'm currently doing. It renders exactly as I'd like it to, aside from the styling. However, I feel that it's deeply hacky: class SettingsForm(ModelForm): class Meta: model = IntegerSetting def as_table(self): bound_field = BoundField(self, self.fields['value'], 'value') return mark_safe("<tr><td><label>%s</label></td><td>%s\n<p class='help'>%s</p></td></tr>" % (self.instance.name, self.instance.description,
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