I am trying to make a 3-dimensional surface plot for the expression: z = y^2/x, for x in the interval [-2,2] and y in the interval [-1.4,1.4]. I also want the z-values to range from -4 to 4.

The problem is that when I'm viewing the finished surfaceplot, the z-axis values do not stop at [-4,4].

So my question is how I can "remove" the z-axis value that range outside the intervall [-4,4] from the finished plot?

My code is:

from mpl_toolkits.mplot3d import axes3d
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.gca(projection="3d")

x = np.arange(-2.0,2.0,0.1,float)       # x in interval [-2,2]
y = np.arange(-1.4,1.4,0.1,float)       # y in interval [-1.4,1.4]
x,y = np.meshgrid(x,y)
z = (y**2/x)                            # z = y^2/x

ax.plot_surface(x, y, z,rstride=1, cstride=1, linewidth=0.25)

ax.set_zlim3d(-4, 4)                    # viewrange for z-axis should be [-4,4] 
ax.set_ylim3d(-2, 2)                    # viewrange for y-axis should be [-2,2] 
ax.set_xlim3d(-2, 2)                    # viewrange for x-axis should be [-2,2] 
plt.show()
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