Why does the equal to operator not work if it is not surrounded by spaces?

I tried the following script:

#!/bin/bash
var1="Test 1" 
var2="Test 2"
if [ "$var1"="$var2" ] 
  then 
    echo "Equal" 
  else 
    echo "Not equal"
fi

It gave me Equal. Although it should have printed Not equal

Only when I inserted space around = it worked as intended:

if [ "$var1" = "$var2" ]

and printed Not equal

Why is it so? Why is "$var1"="$var2" not same as "$var1" = "$var2"?

Moreover, when I wrote if [ "$var1"= "$var2" ], it gave

line 4: [: Test 1=: unary operator expected

What does it mean? How come it's expecting a unary operator?

Edit Report

1 Answer

test (or [ expr ]) is a builtin function. Like all functions in bash, you pass its arguments as whitespace separated words.

As the man page for bash builtins states: "Each operator and operand must be a separate argument."

It's just the way bash and most other Unix shells work.

Variable assignment is different.

In bash a variable assignment has the syntax: name=[value]. You cannot put unquoted spaces around the = because bash would not interpret this as the assignment you intend. bash treats most lists of words as a command with parameters.

E.g.

# call the command or function 'abc' with '=def' as argument
abc =def

# call 'def' with the variable 'abc' set to the empty string
abc= def

# call 'ghi' with 'abc' set to 'def'
abc=def ghi

# set 'abc' to 'def ghi'
abc="def ghi"

answered 2011-02-12T09:43:48.937

Why does the equal to operator not work if it is not surrounded by spaces?

1 Answer

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