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Convert double to string using boost::lexical_cast in C++?

Asked 2011-02-16T12:34:24.323
14

I' d like to use lexical_cast to convert a float to a string. Usually it works fine, but I have some problems with numbers without decimal. How can I fix number of decimal shown in the string?

Example:

double n=5;
string number;
number = boost::lexical_cast<string>(n);

Result number is 5, I need number 5.00.

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3 Answers

31

From the documentation for boost lexical_cast:

For more involved conversions, such as where precision or formatting need tighter control than is offered by the default behavior of lexical_cast, the conventional stringstream approach is recommended. Where the conversions are numeric to numeric, numeric_cast may offer more reasonable behavior than lexical_cast.

Example:

#include <sstream>
#include <iomanip>

int main() {
    std::ostringstream ss;
    double x = 5;
    ss << std::fixed << std::setprecision(2);
    ss << x;
    std::string s = ss.str();
    return 0;
}
answered 2011-02-16T12:36:23.640
3

If you need complex formatting, use std::ostringstream instead. boost::lexical_cast is meant for "simple formatting".

std::string
get_formatted_value(double d) {
    std::ostringstream oss;
    oss.setprecision(3);
    oss.setf(std::ostringstream::showpoint);
    oss << d;
    return oss.str();
}
answered 2011-02-16T12:48:24.003
1

you can also use sprintf, which is faster then ostringstream

#include <cstdio>
#include <string>

using namespace std;

int main()
{
    double n = 5.0;

    char str_tmp[50];
    sprintf(str_tmp, "%.2f", n); 
    string number(str_tmp);
}
answered 2011-02-16T13:23:43.987

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