Alex Rivera | Logout

List<Map<String,Object>> to org.json.JSONObject?

Asked 2009-02-04T18:38:44.533
17
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
Map<String, Object> map = new HashMap<String, Object>();

map.put("abc", "123456");
map.put("def", "hmm");
list.add(map);
JSONObject json = new JSONObject(list);
try {
    System.err.println(json.toString(2));
} catch (JSONException e) {
    e.printStackTrace();
}

What's wrong with this code?

The output is:

{"empty": false}
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3 Answers

2

Also: you could consider using one of other parsers from json.org's list: most of them allow your Json "objects" and "arrays" to map natively to java.util.Maps and java.util.Lists; or in some cases to real Java objects too.

My recommendation would be Jackson, http://jackson.codehaus.org/Tutorial which allows for mapping to List/Map/Integer/String/Boolean/null, as well as to real Beans/POJOs. Just give it the type and it maps data to you, or writes Java objects as Json. Others like "json-tools" from berlios, or google-gson also expose similar functionality.

answered 2009-02-24T20:58:01.997
1

You have a map nested inside a list. you are trying to call the Map without ever iterating through the list first. JSON sometimes feels like magic but in fact it is not. I'll post some code in a moment.
It would be more consistent with JSON to make a Map of Maps instead of a List of Maps.

JSONObject json = new JSONObject(list);
Iterator<?> it = json.keys();
while (keyed.hasNext()) {
    String x = (String) it.next();
    JSONObject jo2 = new JSONObject(jo.optString(x));
}
answered 2009-02-04T18:46:12.287
1

This worked for me:

List<JSONObject> jsonCategories = new ArrayList<JSONObject>();

JSONObject jsonCategory = null;

for (ICategory category : categories) {
    jsonCategory = new JSONObject();
    jsonCategory.put("categoryID", category.getCategoryID());
    jsonCategory.put("desc", category.getDesc());
    jsonCategories.add(jsonCategory);
}
try {
    PrintWriter out = response.getWriter();
    response.setContentType("text/xml");
    response.setHeader("Cache-Control", "no-cache");
    _log.info(jsonCategories.toString());
    out.write(jsonCategories.toString());

} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}
answered 2009-10-15T20:20:13.397

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