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php array_map callback parameter scope

Asked 2011-03-31T19:59:01.757
12

In the following code the callback function passed to wrap_map can't see the argument in the outer function, why? (see code comment for detail)

public static function wrap_implode($ar, $wrap, $delim){
  echo "wrap is $wrap"; //wrap is ok
  $res = array_map(function($val){
     echo "wrap is $wrap"; //wrap is not set here!
     return $wrap. $val . $wrap;
   }, $ar);

   return implode($delim, $res);
}
php scope php-5.3
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1 Answer

23

Because it is in another scope. If you want to use $wrap, try:

function($val) use ($wrap){
   //etc
}

Of course, your function here doesn't need a callback:

return $wrap.implode($wrap.$delim.$wrap,$ar).$wrap;
answered 2011-03-31T20:02:58.537

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