How does a generic constraint prevent boxing of a value type with an implicitly implemented interface?

My question is somewhat related to this one: Explicitly implemented interface and generic constraint.

My question, however, is how the compiler enables a generic constraint to eliminate the need for boxing a value type that explicitly implements an interface.

I guess my question boils down to two parts:

1. What is going on with the behind-the-scenes CLR implementation that requires a value type to be boxed when accessing an explicitly implemented interface member, and

2. What happens with a generic constraint that removes this requirement?

Some example code:

internal struct TestStruct : IEquatable<TestStruct>
{
    bool IEquatable<TestStruct>.Equals(TestStruct other)
    {
        return true;
    }
}

internal class TesterClass
{
    // Methods
    public static bool AreEqual<T>(T arg1, T arg2) where T: IEquatable<T>
    {
        return arg1.Equals(arg2);
    }

    public static void Run()
    {
        TestStruct t1 = new TestStruct();
        TestStruct t2 = new TestStruct();
        Debug.Assert(((IEquatable<TestStruct>) t1).Equals(t2));
        Debug.Assert(AreEqual<TestStruct>(t1, t2));
    }
}

And the resultant IL:

.class private sequential ansi sealed beforefieldinit TestStruct
    extends [mscorlib]System.ValueType
    implements [mscorlib]System.IEquatable`1<valuetype TestStruct>
{
    .method private hidebysig newslot virtual final instance bool System.IEquatable<TestStruct>.Equals(valuetype TestStruct other) cil managed
    {
        .override [mscorlib]System.IEquatable`1<valuetype TestStruct>::Equals
        .maxstack 1
        .locals init (
            [0] bool CS$1$0000)
        L_0000: nop 
        L_0001: ldc.i4.1 
        L_0002: stloc.0 
        L_0003: br.