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I'm kinda waiting for a 'no' answer on this question. I was interested if you can save a variable at the same time when you checking it in an if-clause. Let's say I have this code. if(foo!=null){ if(foo.getBar()!=null){ Bar bar = foo.getBar(); System.out.println("Success: " + bar); } else { System.out.println("Failure."); } } else { System.out.println("Failure."); } I handling now to "failure" -states independently, even if the outcome is the same. I could get them together like this: if(foo!=null && foo.getBar()!=null){ Bar bar = foo.getBar(); System.out.println("Success: " + bar); } else { System.out.println("Failure."); } Much neater code already. if foo is null it will stop there and won't try foo.getBar (in the if) so I won't get a NPE. The last thing i would like to enhance, and the main question: Do I really gave to call on foo.getBar() twice? It would be nice to get away from the second identical call if getBar() would be a very heavy operation. So I am wondering if there is somehow possible to do something similiar to this: if(foo!=null && (Bar bar = foo.getBar())!=null){ Bar bar = foo.getBar(); System.out.println("Success: " + bar); } else { System.out.println("Failure."); } I would have to break it up to two different if's again if I would like to do Bar bar = foo.getBar(); if (bar!=null) ...

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