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class A : public B { ... } // case I : explicitly call the base class default constructor A::A() : B() { ... } // case II : don't call the base class default constructor A::A() // : B() { ... } Is the case II equal to case I? To me, I assume that the default constructor of base class B is NOT called in case II. However, despite still holding this assumption, I have run a test which proves otherwise: class B { public: B() { cout << "B constructor" << endl; } }; class A : public B { public: A() { cout << "A constructor" << endl; } }; int _tmain(int argc, _TCHAR* argv[]) { A a; return 0; } // output from VS2008 B constructor A constructor Press any key to continue . . .
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