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SQL Server Query LEFT JOIN, SUM and GROUP BY and I'm stumped!

Asked 2011-05-03T17:19:23.827
11

I am beating my brain against this one

I have 3 SQL Server 2005 tables

userawards:

id, awardamount, userid, dateawarded, awardtypeid

user:

id, firstname, lastname

awardtypes: 

id, title

So if the awards table had the rows

1, 300.00, 3, 01-01-2011, 1
2, 125.00, 3, 01-05-2011, 1
3,  50.00, 2, 01-05-2011, 2

user table rows

1, john, smith
2, mark, smith
3, bob, smith

award types

1, cash
2, prize

and I want the output to look similar to this

bob smith, 425.00, cash
mark smith, 50, prize

etc etc.

A user can have multiple awards, the results need to display unique users, but with there total award amount. in addition there needs to be 2 joins, one, to grab the users first name/last that's in a user table and the award type title.

So my query is looking like this (i know it doesn't work)

SELECT id, userid, awardtypeid, SUM(awardamount) 
FROM awards a
LEFT JOIN userinfo ui ON ui.userid = a,userid
LEFT JOIN awardtypes ON awardtypesid = a.awardtypeid
GROUP BY userid

Is this even possible?

sql-server join group-by sum
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1 Answer

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If I understand this correctly, there should be no more than one row per user and you need a total award amount per user. On other side you want to know what kind of awards every user had. You can show comma delimited list of awards for every user:

select 
    usr.FirstName,
    usr.LastName, 
    awd.AwardAmount,
    AwardTypes = (   
        select Title + ','
        from UserAwards uaw
            join AwardTypes awt on
                uaw.AwardTypeId = awt.Id
        where uaw.UserId = usr.id
        for xml path(''))
from [User] usr
    join (
        select UserId, sum(AwardAmount) AwardAmount
        from UserAwards uaw
        group by UserId
    ) awd on
        awd.UserId = usr.Id
answered 2011-05-03T18:27:35.290

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