KnowledgeHub
Questions
Tags
Users
Search
Alex Rivera
|
Logout
Edit Question
Title
Body
When I run this: import urllib feed = urllib.urlopen("http://www.yahoo.com") print feed I get this output in the interactive window (PythonWin): <addinfourl at 48213968 whose fp = <socket._fileobject object at 0x02E14070>> I'm expecting to get the source of the above URL. I know this has worked on other computers (like the ones at school) but this is on my laptop and I'm not sure what the problem is here. Also, I don't understand this error at all. What does it mean? Addinfourl? fp? Please help.
Tags (comma-separated)
Save Edits
Cancel