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Alex Rivera
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I'm writing a generalized function wrapper, that can wrap any function into a lua-style call, which has the form int lua_function( lua_State *L) And I wish the wrapper function is generated on-the-fly, so I'm thinking of passing the function as a template argument. This is trivial if you know the number (e.g, 2) of arguments: template <typename R, typename Arg1, typename Arg2, R F(Arg1, Args)> struct wrapper However, I don't know the number, so I beg for variadic template argument for help // This won't work template <typename R, typename... Args, R F(Args...)> struct wrapper The above won't compile, since variadic argument has to be the last one. So I use two level template, the outer template captures types, the inner template captures the function: template <typename R, typename... Args> struct func_type<R(Args...)> { // Inner function wrapper take the function pointer as a template argument template <R F(Args...)> struct func { static int call( lua_State *L ) { // extract arguments from L F(/*arguments*/); return 1; } }; }; That works, except that to wrap a function like double sin(double d) {} the user has to write func_type<decltype(sin)>::func<sin>::apply which is tedious. The question is: is there any better, user-friendlier way to do it? (I can't use a function template to wrap the whole thing, coz a function parameter can't be used as a template argument.)
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