WPF: How do I set the Owner Window of a Dialog shown by a UserControl?

I've got a WPF application with these three types of things...

WindowMain
UserControlZack
WindowModal

UserControlZack1 sits on my WindowMain...

<Window x:Class="WindowMain"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:local="clr-namespace:ProjectName"
        ...
        Name="WindowMain">
    <Grid>
        ...
        <local:UserControlZack x:Name="UserControlZack1" ... />
        ...
    </Grid>
</Window>

UserControlZack1 displays a WindowModal dailog box...

Partial Public Class UserControlZack

   ...

    Private Sub SomeButton_Click(...)
        'instantiate the dialog box and open modally...
        Dim box As WindowModal = New WindowModal()
        box.Owner = ?????
        box.ShowDialog()
        'process data entered by user if dialog box is accepted...
        If (box.DialogResult.GetValueOrDefault = True) Then
            _SomeVar = box.SomeVar
            ...
        End If
    End Sub

End Class

How do I set box.Owner to the correct Window, my running instance of WindowMain?

I cannot use box.Owner = Me.Owner, because "'Owner' is not a member of 'ProjectName.UserControlZack'."

I cannot use box.Owner = Me.Parent, because that returns a Grid, not the Window.

I cannot use box.Owner = WindowMain, because "'WindowMain' is a type and cannot be used as an expression."

Edit Report

Updating to try and help Greg from the comments. The command works in the main windows menu, the button in the user control and the context menu in the user control.

I'd do it with commands. So have a class Commands.cs something like:

public static class Commands
{
    public static RoutedUICommand TestShowDialogCommand = new RoutedUICommand("Test command", "TestShowDialog", typeof(Commands));
}

    public Window1()
    {
        InitializeComponent();

        CommandManager.RegisterClassCommandBinding(typeof(System.Windows.Controls.Control),
            new CommandBinding(Commands.TestShowDialogCommand, ShowDialogCommand, CanShowDialogCommand));
    }

    private void ShowDialogCommand(object sender, ExecutedRoutedEventArgs e)
    {
        var box = new Window();
        box.Owner = this;
        box.ShowDialog();

    }

    private void CanShowDialogCommand(object sender, CanExecuteRoutedEventArgs e)
    {
        e.CanExecute = true;
    }

This is my xaml for the main window:

<Window x:Class="WpfApplication1.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:WpfApplication1="clr-namespace:WpfApplication1"
Title="Window1" Height="300" Width="322">
<Grid>
    <StackPanel>
        <Menu>
            <MenuItem Header="Test">
                <MenuItem Header="ShowDialog" Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}"/>
            </MenuItem>
        </Menu>
        <WpfApplication1:BazUserControl />
    </StackPanel>
</Grid>
</Window>

This is the xaml for my user control (default code behind only)

<UserControl x:Class="WpfApplication1.BazUserControl"
xmlns="http://schemas.mic


                        
                        
                            answered 2009-03-03T17:51:58.640

WPF: How do I set the Owner Window of a Dialog shown by a UserControl?

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