I haven't really used bitwise enums before, and I just want to make sure my testing is correct. I am most interested in testing for the values None and All. We receive data from a webservice that utilises this enum to categorise certain pieces of the data. Given that, I am assuming that nether None nor All would ever be combined with any other value.
Given the following bitwise enum definition;
[System.FlagsAttribute()]
public enum TrainingComponentTypes : int
{
None = 0,
AccreditedCourse = 1,
Qualification = 2,
Unit = 4,
SkillSet = 8,
UnitContextualisation = 16,
TrainingPackage = 32,
AccreditedCourseModule = 64,
All = 127,
}
I read the following quote on this MSDN site about FlagAttributes;
Use None as the name of the flag enumerated constant whose value is zero. You cannot use the None enumerated constant in a bitwise AND operation to test for a flag because the result is always zero. However, you can perform a logical, not a bitwise, comparison between the numeric value and the None enumerated constant to determine whether any bits in the numeric value are set.
Does a logical comparison in this instance refer to a normal equality test for enums? For example;
TrainingComponentTypes tct = TrainingComponentTypes.None;
if (tct == TrainingComponentTypes.None)
{ ... }
For a bitwise comparison, I am performing the following;
TrainingComponentTypes tct = TrainingComponentTypes.AccreditedCourse | TrainingComponentTypes.Qualification | TrainingComponentTypes.TrainingPackage;
Assert.IsTrue((tct & TrainingComponentTypes.AccreditedCourse) == TrainingComponentTypes.AccreditedCou