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Why does the =~ operator only sometimes have side effects?

Asked 2011-05-25T12:32:52.653
12

I've noticed a side effect in Ruby/Oniguruma that is only present in 1 out of 4 seemingly equivalent statements. Why is the variable day defined in 009, but not in 003, 005 or 007?

irb(main):001:0> r = /(?<day>\d\d):(?<mon>\d\d)/
=> /(?<day>\d\d):(?<mon>\d\d)/

irb(main):002:0> r =~ "24:12"
=> 0
irb(main):003:0> day
NameError: undefined local variable or method `day' 

irb(main):004:0> "24:12" =~ r
=> 0
irb(main):005:0> day
NameError: undefined local variable or method `day'


irb(main):006:0> "24:12" =~ /(?<day>\d\d):(?<mon>\d\d)/
=> 0
irb(main):007:0> day
NameError: undefined local variable or method `day'


irb(main):008:0> /(?<day>\d\d):(?<mon>\d\d)/ =~ "24:12"
=> 0
irb(main):009:0> day
=> "24"

nb#1: It's the same regex and the same string in all four cases.

nb#2: I've verified the behavior in MS Windows and Ubuntu Linux.

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1 Answer

13

When you call "24:12" =~ r you actually call "24:12".=~(r). So, String#=~ just returns the position the match starts, or nil if there is no match.

But when you call /(?<day>\d\d):(?<mon>\d\d)/ =~ "24:12" you actually call Regexp#=~

And as the documentation says

If =~ is used with a regexp literal with named captures, captured strings (or nil) is assigned to local variables named by the capture names.

what about 003:

The assignment is not occur if the regexp is not a literal.

   re = /(?<lhs>\w+)\s*=\s*(?<rhs>\w+)/
   re =~ "  x = y  "
   p lhs    # undefined local variable
   p rhs    # undefined local variable

and

The assignment is not occur if the regexp is placed at right hand side.
" x = y " =~ /(?<lhs>\w+)\s*=\s*(?<rhs>\w+)/
p lhs, rhs # undefined local variable

answered 2011-05-25T12:49:31.890

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