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In Java, I want to convert a double to an integer, I know if you do this: double x = 1.5; int y = (int)x; you get y=1. If you do this: int y = (int)Math.round(x); You'll likely get 2. However, I am wondering: since double representations of integers sometimes look like 1.9999999998 or something, is there a possibility that casting a double created via Math.round() will still result in a truncated down number, rather than the rounded number we are looking for (i.e.: 1 instead of 2 in the code as represented) ? (and yes, I do mean it as such: Is there any value for x, where y will show a result that is a truncated rather than a rounded representation of x?) If so: Is there a better way to make a double into a rounded int without running the risk of truncation? Figured something: Math.round(x) returns a long, not a double. Hence: it is impossible for Math.round() to return a number looking like 3.9999998. Therefore, int(Math.round()) will never need to truncate anything and will always work.

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