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Alex Rivera
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Using true closures, we can do, function foo(&$ref) { $inFn = function() use (&$ref) { $ref = 42; }; $inFn(); } thus modifying the reference without having to pass it in the call to $inFn . If we replace, $inFn = function(... with $inFn = create_function(... is there any (simple and clean) way to do the same thing; refer to a variable of the containing scope by reference without explicitly passing it into $inFn ?
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