Do smart pointers work with arrays allocated using new T[]?

How do smart pointers handle arrays? For example,

void function()
{
    std::unique_ptr<int> my_array(new int[5]);
}

When my_array goes out of scope and gets destructed, does the entire integer array get re-claimed? Is only the first element of the array reclaimed? Or is there something else going on (such as undefined behavior)?