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Alex Rivera
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I need to copy from input document to output document all attributes but one. My input is like this: <mylink id="nextButton" type="next" href="javascript:;" /> And I need output like this: <a id="nextButton" href="javascript:;" /> If I use the following XSL: <xsl:template match="mylink"> <a><xsl:copy-of select="attribute::*"/></a> </xsl:template> I get all attributes to output like this: <a id="nextButton" type="next" href="javascript:;" /> But I want to ignore the "type" attribute. I've tried the following but none of them seems to work the way I need: <xsl:copy-of select="attribute::!type"/> <xsl:copy-of select="attribute::!'type'"/> <xsl:copy-of select="attribute::*[!type]"/> <xsl:copy-of select="attribute::not(type)"/> How should I write my stylesheet to get needed output?
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